## Frequency Equations

$c=\lambda v$

alanaarchbold
Posts: 68
Joined: Fri Sep 28, 2018 12:27 am

### Frequency Equations

I know some people were saying that there's an equation that combines E=(-hR)/(n^2) and E=hV. Does anyone know what it is?

Henry_Phan_4L
Posts: 68
Joined: Fri Sep 28, 2018 12:24 am

### Re: Frequency Equations

You might be talking about the equation that combines E=hv with c=λv. Substitute v to get E=hc/λ.

Andie Jian 1D
Posts: 69
Joined: Fri Sep 28, 2018 12:17 am
Been upvoted: 1 time

### Re: Frequency Equations

The textbook gives us the Rydberg formula, which is $\nu = R \left \{ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right \}$
So I think it has to have something to do with combining the equations E=hv, and E=-hR/n^2 , so you get v=-R/n^2. Then, if you were trying to find v1-v2, you would get $\nu = -R \left \{ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right \}$
However, this leaves you with -R in the equation, unlike the Rydberg formula, so I'm still a bit confused too.