CHEMISTRY COMMUNITY

Posted: **Sat Oct 13, 2018 2:54 pm**

I know some people were saying that there's an equation that combines E=(-hR)/(n^2) and E=hV. Does anyone know what it is?

Posted: **Sat Oct 13, 2018 3:00 pm**

You might be talking about the equation that combines E=hv with c=λv. Substitute v to get E=hc/λ.

Posted: **Sat Oct 13, 2018 3:12 pm**

The textbook gives us the Rydberg formula, which is $\nu = R \left \{ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right \}$
So I think it has to have something to do with combining the equations E=hv, and E=-hR/n^2 , so you get v=-R/n^2. Then, if you were trying to find v1-v2, you would get $\nu = -R \left \{ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right \}$
However, this leaves you with -R in the equation, unlike the Rydberg formula, so I'm still a bit confused too.

CHEMISTRY COMMUNITY

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