## Photoelectric Effect Module #28

$c=\lambda v$

Lauryn Shinno 2H
Posts: 59
Joined: Fri Sep 28, 2018 12:24 am

### Photoelectric Effect Module #28

How do you solve this? Light hits a sodium metal surface and the velocity of the ejected electron is 6.61x10^5 m.s-1. The work function for sodium is 150.6 KJ.mol-1. a. What is the KE of the ejected electron? b. How much energy is required to remove an electron from one sodium atom? c. What is the frequency of the incident light on the sodium metal surface?

Elena Saab 4A
Posts: 43
Joined: Fri Sep 28, 2018 12:27 am

### Re: Photoelectric Effect Module #28

a. Kinetic energy= 1/2(mv^2), and the mass of an electron is 9.109x10^-31 kg.
b. I believe the energy here required to to remove 1 sodium electron would be equal to the work function.
c. the Energy of the photon = work function + kinetic energy. If you find the energy, you also know that E=hv, (v=frequency), so v=h/E!