## Light Intensity

$c=\lambda v$

Emily Orozco L4
Posts: 45
Joined: Fri Sep 28, 2018 12:29 am

### Light Intensity

What happens if the energy per photon is greater than the energy needed to remove an electron?

405169322
Posts: 22
Joined: Fri Sep 28, 2018 12:25 am

### Re: Light Intensity

Using this equation: E(photon) - E(removed e-) = E(kinetic). you can solve for the difference in energy for kinetic.

Posts: 14
Joined: Fri Sep 28, 2018 12:18 am

### Re: Light Intensity

The difference between energy per photon E(photon) and the energy needed to remove an electron E(e-) would give you the kinetic energy E(k).
E(photon) - E(e-) = E(k)
In turn, E(k) = 1/2 MV^2, where M is the mass of the electron and V is the velocity of the electron.

WilliamNguyen_4L
Posts: 65
Joined: Fri Sep 28, 2018 12:28 am

### Re: Light Intensity

The energy of the photon must be equal to or greater than the energy required to remove an electron. Therefore, if the photon energy is greater, then the electron will be removed. However, due to conservation of energy there will be an excess of energy. The excess energy can be identified as the kinetic energy of the electron. Higher energy photons than necessary will result in electrons being emitted with higher kinetic energy.