Inverse Relationships?


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Saleha_Mian_3E
Posts: 32
Joined: Fri Sep 28, 2018 12:25 am

Inverse Relationships?

Postby Saleha_Mian_3E » Fri Oct 19, 2018 2:20 pm

Can someone explain why the relationship of frequency and wavelength is inversely related? Also what are the units of frequency and wavelength?

Alma Carrera 3C
Posts: 33
Joined: Fri Apr 06, 2018 11:02 am

Re: Inverse Relationships?

Postby Alma Carrera 3C » Fri Oct 19, 2018 2:40 pm

if you refer back to the equation: speed of light(c)=wavelength(lambda) x frequency(v) you'll see that the product of wavelength times frequency must equal the speed of light which is a set value. Therefore when the wavelength decreases the frequency must increase and vice versa. The units for wavelength are usually nanometers (nm) or sometimes in meters (m) and the units of frequency are Hz or s^-1.

Michael Novelo 4G
Posts: 64
Joined: Fri Sep 28, 2018 12:28 am

Re: Inverse Relationships?

Postby Michael Novelo 4G » Fri Oct 19, 2018 7:55 pm

Also if you rearrange the equation to Wavelength = c/v if frequency (v) is larger than we know that wavelength is smaller and if its the opposite where frequency (v) is smaller the wavelength will be bigger. This also woks when Frequency (v) = c/wavelength. Also the units for wavelength are typically given in nanometers (nm) but in calculations we use meters (m) I believe so we would multiply the nanometers x 10^-9 to convert to meters. Frequency is Hz or s^-1 when doing calculations.

Anmol_cheema_2F
Posts: 60
Joined: Fri Sep 28, 2018 12:26 am

Re: Inverse Relationships?

Postby Anmol_cheema_2F » Fri Oct 19, 2018 8:25 pm

In the equation (c)=wavelength(lambda) x frequency(v), the speed (c) is a constant. Therefore if wavelength increases, frequency must decrease and vice versa because c must remain the same.

Rosha Mamita 2H
Posts: 63
Joined: Fri Sep 28, 2018 12:19 am

Re: Inverse Relationships?

Postby Rosha Mamita 2H » Fri Oct 19, 2018 9:05 pm

when there are an increased number of oscillations in a certain amount of time (frequency), the distance between the peaks (wavelength) decrease, and vise versa


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