b15


Moderators: Chem_Mod, Chem_Admin

Post Reply
Jasmin Argueta 1K
Posts: 69
Joined: Fri Sep 28, 2018 12:16 am

b15

Postby Jasmin Argueta 1K » Thu Oct 25, 2018 1:09 am

For part C of problem b15 I was wondering why you do 1.66x106^-17J plus 1/2mv^2. I thought the equation was E(k)=1/2mv^2. why are we adding 1.66x106^-17J?
Top
Sabrina Ryu 3L
Posts: 30
Joined: Fri Sep 28, 2018 12:26 am

Re: b15

Postby Sabrina Ryu 3L » Thu Oct 25, 2018 1:15 am

Hi, 1.66x106^-17J is the work function! So it is following the equation (1/2)mv^2 = hv - (work function). It is just rearranged so you can find the energy (hv).
Top
Helen Mejia 1I
Posts: 67
Joined: Fri Sep 28, 2018 12:24 am

Re: b15

Postby Helen Mejia 1I » Thu Oct 25, 2018 9:57 pm

You need to find the energy of the photon in order to find the wavelength.
The formula to find the energy of a photon is the work function plus kinetic energy.
Work function is 1.66 x 10^-17 J a
Kinectic Energy: 1/2(m)(v^2)
Top
Post Reply

Return to “Properties of Light”

Who is online

Users browsing this forum: No registered users and 6 guests