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I think it is more conceptual, but also has to do with calculating the distances between spectral lines as was explained through the sketch during the last lecture. Visible light has smaller gaps between lines whereas ultraviolet has ones farther apart so the value of change in E is greater.
Well, it is relevant in that visible light corresponds to the Balmer series. So, when we are given the wavelength of emitted light (and it is in the visible portion of the spectrum) and we have to find the initial and final n, we know that the final n is 2. And we can get the energy and frequency from the wavelength with the E=hv and c=λv equations.
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