## Homework B9

$c=\lambda v$

Edmund Zhi 2B
Posts: 118
Joined: Sat Jul 20, 2019 12:16 am

### Homework B9

How are we supposed to know how many photons are released? I'm confused. I've started with E = h (c/lambda) and got 4.73 x 10^-19 but I don't know where to go from there

Samuel Tzeng 1B
Posts: 103
Joined: Sat Aug 24, 2019 12:15 am

### Re: Homework B9

find number of joules from the light
32J/s * 2.0s = 64J

then divide joules by the energy per photon
64J/(4.7*10^-19) = 1.4*10^20