## atomic spectra module

$c=\lambda v$

Katherine Wu 1H
Posts: 104
Joined: Fri Aug 30, 2019 12:15 am
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### atomic spectra module

The meter was defined in 1963 as 1,650,763.73 wavelengths of radiation emitted by krypton-86 (it has since been redefined). What is the wavelength of this krypton-86 radiation? What is the wavelength of this krypton-86 radiation? To what region of the electromagnetic spectrum does this wavelength correspond (i.e. infrared, UV, x-ray, etc.)? What energy does this one photon of this radiation have?

EvaLi_3J
Posts: 53
Joined: Wed Oct 02, 2019 12:16 am

### Re: atomic spectra module

First, you can calculate the wavelength. Since you know that one meter is composed of 1,650,763.73 wavelengths of radiation emitted by krypton-86, you can basically divide one meter by this number, and you get the length of one wavelength.

In terms of region, you can just check the spectrum and see what wavelengths of light correspond to what types of light. Normally, a wavelength between 400nm to 700 nm corresponds to visible light.

Lastly, in terms of energy, you should just use the equation E = h*frequency to calculate the energy of an electron.

Hope that helps.