## Video module test Question-ATOMIC SPECTRA

$c=\lambda v$

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derinceltik1K
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Joined: Sat Aug 17, 2019 12:15 am

### Video module test Question-ATOMIC SPECTRA

The meter was defined in 1963 as 1,650,763.73 wavelengths of radiation emitted by krypton-86 (it has since been redefined). What is the wavelength of this krypton-86 radiation? To what region of the electromagnetic spectrum does this wavelength correspond (i.e. infrared, ultraviolet, x-ray, etc.)? What energy does one photon of this radiation have?

How would we solve this question?

Jack Riley 4f
Posts: 100
Joined: Sat Aug 24, 2019 12:17 am

### Re: Video module test Question-ATOMIC SPECTRA

you must first find the wavelength of krypton-86 radiation. To do this, divide 1 meter by 1650763.73 to find the length of the wavelength. This gives you a wavelength of 6.06x10^-7 or 606 nm. This is visible light. To find the energy we must use E=hv=(hc)/(lambda)=3.28x10^-19

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