1A.15


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304976622
Posts: 25
Joined: Wed Nov 15, 2017 3:01 am

1A.15

Postby 304976622 » Sun Nov 03, 2019 8:21 pm

In the ultraviolet spectrum of atomic hydrogen, a line is observed at 102.6 nm. Determine the values of n for the initial and final energy levels of the electron during the emission of energy that leads to this spectral line.

I got 2.9x10^15=3.28x10^15{1/1^2-1/n^2} (is this right?)

I understand that we have to solve for n^2 however I'm confused on how to enter this problem into my calculator. Where do I start?

Cynthia Rodas 4H
Posts: 51
Joined: Wed Sep 18, 2019 12:21 am

Re: 1A.15

Postby Cynthia Rodas 4H » Sun Nov 03, 2019 8:45 pm

Yes! Great start so far. From here, you would try to get by itself by moving all other values to the other side to get:


From here, you would solve the left side which is approximately:


Then you would get n22 by itself to get:

which is approximately 9.

Next, you would find the square root to get n2 which is 3.

304976622
Posts: 25
Joined: Wed Nov 15, 2017 3:01 am

Re: 1A.15

Postby 304976622 » Sun Nov 03, 2019 8:52 pm

Cynthia Rodas 4H wrote:Yes! Great start so far. From here, you would try to get by itself by moving all other values to the other side to get:


From here, you would solve the left side which is approximately:


Then you would get n22 by itself to get:

which is approximately 9.

Next, you would find the square root to get n2 which is 3.

Great thank you!!!

Hailey Kim 4G
Posts: 110
Joined: Sat Jul 20, 2019 12:16 am

Re: 1A.15

Postby Hailey Kim 4G » Wed Nov 06, 2019 1:12 pm

How do you know that n1=1?


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