1A.15

[304976622]

In the ultraviolet spectrum of atomic hydrogen, a line is observed at 102.6 nm. Determine the values of n for the initial and final energy levels of the electron during the emission of energy that leads to this spectral line.

I got 2.9x10^15=3.28x10^15{1/1^2-1/n^2} (is this right?)

I understand that we have to solve for n^2 however I'm confused on how to enter this problem into my calculator. Where do I start?

[Cynthia Rodas 4H]

Yes! Great start so far. From here, you would try to get by itself by moving all other values to the other side to get:


From here, you would solve the left side which is approximately:


Then you would get n₂² by itself to get:

which is approximately 9.

Next, you would find the square root to get n₂ which is 3.

[304976622]

Yes! Great start so far. From here, you would try to get by itself by moving all other values to the other side to get:


From here, you would solve the left side which is approximately:


Then you would get n₂² by itself to get:

which is approximately 9.

Next, you would find the square root to get n₂ which is 3.

Great thank you!!!

[Hailey Kim 4G]

How do you know that n1=1?