% Yield

Moderators: Chem_Mod, Chem_Admin

Zane Mills 1E
Posts: 80
Joined: Fri Sep 25, 2015 3:00 am
Been upvoted: 1 time

% Yield

Postby Zane Mills 1E » Wed Sep 30, 2015 8:31 pm

suppose 68.5kg of CO is reacted with 8.60kg of H2....calculate the percent yield of methanol if 3.57 x 10^4g of CH3OH is ACTUALLY produced. I got everything leading up to this question I am just super confused as to what it is asking and how to get there.

Posts: 18898
Joined: Thu Aug 04, 2011 1:53 pm
Has upvoted: 717 times

Re: % Yield

Postby Chem_Mod » Wed Sep 30, 2015 8:39 pm

Once you have determined limiting reagent and used stoichiometry, you will have found the THEORETICAL yield of methanol.

the experimental (actual) yield of methanol divided by the theoretical yield gives the % yield

Sina Rahmani 4A
Posts: 27
Joined: Fri Sep 25, 2015 3:00 am

Re: % Yield

Postby Sina Rahmani 4A » Fri Oct 02, 2015 11:20 am

Theoretical yield is the amount of a substance one has at the end of an experimental calculation. So whenever you are solving problems, the answer you find when you do all of those mole conversions is the THEORETICAL. The actual yield is the one found in the lab, and the point of the percent yield is to determine how close the lab result is to the calculation from the mole conversions. Since you are looking for a percent, the actual value (the one you find in the lab) is divided by the theoretical value, and then you multiply by 100%.

Posts: 43
Joined: Fri Sep 25, 2015 3:00 am

Re: % Yield

Postby 704628249 » Wed Dec 02, 2015 6:32 pm

Just remember this simple formula: actual/theoretical * 100

Posts: 22
Joined: Sat Jul 09, 2016 3:00 am

Re: % Yield

Postby Aleena_Sorf_2A » Thu Sep 29, 2016 11:35 pm

In this problem, we are given the masses of the reactants and the actual yield. We are asked to calculate the percent yield, which can be solved by this formula:
Percent Yield= (Actual Yield/Theoretical Yield) x 100
However, we first need to find the theoretical yield, which can be done by solving for the limiting reactant. Once found, you just plug in the values of actual yield for methanol and theoretical yield for methanol into the equation written above and you get the percent yield.

Posts: 51
Joined: Wed Sep 21, 2016 3:00 pm

Re: % Yield

Postby Mirian_Garcia_2G » Fri Sep 30, 2016 12:56 am

So, using the information provided, you can definitely come up with a chemical equation for the rxn. This will allow you to better understand what is occurring within the reaction. The formula for % yield is:

Percent Yield= (Actual Yield/Theoretical Yield)x100%

Return to “Properties of Light”

Who is online

Users browsing this forum: No registered users and 2 guests