## Wavelength

$c=\lambda v$

Leslie Romo 1C
Posts: 21
Joined: Fri Sep 25, 2015 3:00 am

### Wavelength

The problem is "What is the wavelength of the radiation emitted when an electron transitions from n=4 to n=3." I am bit confused on how to set up the formula. Would this be the formula:
ΔE=-hR(1/n^2-1/n^2)

The first 'n' being n=4 and the second n=3?? how do we know which one is which?

Brandon Truong 2G
Posts: 29
Joined: Fri Sep 25, 2015 3:00 am

### Re: Wavelength

The formula you use is similar to that one. The formula is $\upsilon = R(\frac{1}{n_{1} ^2}-\frac{1}{n_{2} ^2})$

The first n is 3 and the second n is 4. The reason is because a photon is released when an electron falls from a higher energy level to a lower energy level. The equation is based on Final minus Initial. Since n=3 is the final and n=4 is the initial, the first n is 3 and the second n is 4.