What exactly is Φ?

[Nane Onanyan 1G]

I understand that this is used in the work function, but how is it calculated? Is it just h(v)?

[Alexa Pham 1D]

I think it's usually a value that's given in an equation. Or you could solve for it if they give you the energy of the photon. If that's the case, then you'd have to make the kinetic energy portion equal to 0 in order to find the minimum amount of energy (aka work function) needed to emit an electron from that metal.

[KatarinaReid_3H]

Yes, the work function is the energy. In problems, it will usually give this value in Joules or eV(electron volt). 1eV is equal to 1.6 x 10^-19 Joules.

[Andrew Wang 1C]

Φ is the amount of energy (unique to each element) that a photon needs to have for an electron to be ejected from a metal when it is hit with the proton. E = hv is the energy of a photon when it hits the metal (hv = Φ + E_k). So Φ would be equal to hv only if the electron is ejected with no excess energy.

I think Φ will be given to us in problems. Or we could also be solving for Φ, if the problem gives us enough info (hv and E_k).

Hope this helps!

[Nika Gladkov 1A]

is defined as the amount of energy required to remove an electron from a metal surface in a vacuum with the electron having 0 KE. You would calculate it by using the equation E(photon)- = E(excess) (or the kinetic energy). If you know the frequency of incoming light, you can use to calculate it's energy. Then, if you are given the velocity of the outgoing electron, you can use it to calculate the kinetic energy through the equation . Then, you would subtract the E of the incoming photon from the KE of the outgoing electron to get the work function. If the velocity of the outgoing electron is zero, the energy of the incoming photon is equal to the work function.

[Shrey Pawar 2A]

The Φ symbol is just meant to represent the work function which shows the threshold energy needed to excite the electron. Most of the time it is provided in the context of the problem, or you could use the equation that Alexa provided to find it, given you have the rest of the variables already. H(v) is just the energy of the photon so that is not the same thing. The h(v) in the equation is just there to show the intial amount of energy. When it is subtracted by the work function, we get the excess energy remaining, which is the kinetic energy of the electron excited. Hope this helps sorry it's a bit wordy!

[Malakai Espinosa 3E]

Φ is described as the work function/threshold energy, but I don't believe there is an equation that we need to know in order to get the value on our own. This number is more determined through experimental data, and therefore beyond the scope of this class. If the work function is needed then the problem will give it to you, unless of course the problem is asking you to solve this variable.

Hope this helps!

[Tessa House 3A]

This is the work function, which tells you the energy required to remove one electron from the metal. It can be given in problems in J or kJ, but in the case it is given in kJ/mol for a metal, you might need to calculate the energy required to remove one electron rather than one mole to solve other parts of the problem. You can also use the energy of the incoming light and kinetic energy to calculate it.

[Nicoli Peiris 1B]

This is the work function. To solve for this you would have to given some way to solve for or directly given the kinetic energy of the electron and the energy of the photon. Otherwise you would be given the work function value and would be asked to solve for something related to the kinetic energy or the energy of the photon.

[Margaret Wang 2D]

The work function is also known as the threshold energy, the energy needed to eject an electron. From what I understand, we will always be given the value. If we need to solve for it, it'll be with the equation E(photon) - (work function) = E(excess) and never any other way.

[Aydin Karatas 1F]

It is the work energy. When looking at work energy in a problem, it's usually measured in Joules (J) of electronvolts (eV). Keep in mind that the work energy plus the excess energy (kinetic energy of an electron) is equal to the incoming energy of the photon.

Hope this helps!

[Tiao Tan 3C]

It is the work function/threshold energy: the energy to remove electrons. It is usually given in the question so you don't have to worry! If not, then you would have to find it using the equation hv=Ek + Φ. I am sure the other conditions will be given for you to apply this equation.

[Ximeng Guo 2K]

Energy required to remove an electron from the metal surface.

Total Energy provided by photons = energy required to remove 1 e- + kinetic energy of that removed e-

[Simer_Shera_2D]

The work function is the energy required to remove a single electron from a specific surface. From my understanding and the practice problems that I've done, it's always provided in the problem and does not need to be solved for.

[Lorraine Jiang 2C]

The work function, which is also called the threshold energy, is the minimum amount of energy required for the e- on an atom to be removed!

Hope it helps!

[Jiapeng Han 1C]

Work function is the threshold energy--the minimum amount of energy needed to release electrons from a metal surface. Too calculate it, you need to know exactly at which frequency of light does the electrons get released. Then simply use the equation: E=h*f. If the energy of light is big enough to release electrons from metal surface, then to calculate the work function, you need to use the energy of the light to subtract the kinetic energy of the released electrons.

[Shrinidhy Srinivas 3L]

I think the most important thing that you need to remember about the work function is that it represents the threshold energy. The amount of energy that the photon comes in with minus the threshold energy gives you the kinetic energy of the ejected electron. Hope this helps!