Sapling hw question old

[Juliana Rosales 1H]

Hey yall I had a problem with this hw question on sapling .

When a metal was exposed to photons at a frequency of 1.23×1015 s−1, electrons were emitted with a maximum kinetic energy of 3.60×10−19 J.
Calculate the work function, Φ, of this metal.

I calculated it and got 4.55 x 10^19, and it said that it was right.
The second part goes
What is the maximum number of electrons that could be ejected from this metal by a burst of photons (at some other frequency) with a total energy of 3.02×10−7 J?

From my understanding I was supposed to divide 3.02x10^-7 by 4.55 x 10^19 and call it a day.
HOWEVER THIS WAS NOT THE CASE AND I DIDN'T FINISH THE QUESTION. Either way I am super confused as to what the right answer was or how I would get it, so please help.

[Jillian Labador 3E]

Hi! I believe you did the question right; however, I think the work function has a negative exponent of -19 and not +19, so it could've been a calculating error? Dividing the total energy (3.02x10^-7 J) by the work function (4.55x10^-19 J/photon) should have yielded the number of photons absorbed, which is equal to the number of electrons ejected. The answer would then be 6.64x10^11 electrons. If a positive exponent was used, then the answer would've been 6.64x10^-27 which wouldn't make sense because 0.0000....664 of an electron can't be admitted. Hope this helps!

[Juliana Rosales 1H]

Thank you so much for your help! It totally makes sense.

[Erika Sosa-Cruz 1J]

I was wondering about the how NA+ reacts