Question 8 on the achieve hw?

[Shaleena 3C]

Calculate the wavelength, in nanometers, of the spectral line produced when an electron in a hydrogen atom undergoes the transition from the energy level n=4 to the level n=1.

Thank you :)

[Sophia Zhao]

Use the equation: v = R[1/(n final^2) - 1/(n initial^2)]. Where n initial = 4 and n final = 1. Use this to find frequency. Then use c = v*lambda to find wavelength.

[Jericho Ansay 1C]

Essentially, you will be using the c = lambda x frequency equation and the Rydberg equation. Your Rydberg equation is v = R [(1/n1^2) - (1/n2^2)]. Plugging in 1 and 4 for n1 and n2, you get your v to equal around 3.08 x 10^15 s^-1. To solve for wavelength, you isolate lambda and divide the speed of light (c) by the calculated value for frequency, getting (3.00 x 10^8 m/s)/(3.08 x 10^15 s^-1) = 9.72 x 10^-8 m or around 97.2 nm.