Achieve Hw #8
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Achieve Hw #8
Hi!
I am very confused on how to start question 8 of our homework, can anyone give me any advice?
"Calculate the wavelength, in nanometers, of the spectral line produced when an electron in a hydrogen atom undergoes the transition from the energy level n=6
to the level n=1."
I am very confused on how to start question 8 of our homework, can anyone give me any advice?
"Calculate the wavelength, in nanometers, of the spectral line produced when an electron in a hydrogen atom undergoes the transition from the energy level n=6
to the level n=1."
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Re: Achieve Hw #8
Hi,
You can use v=R to calculate the frequency, then use c/v to calculate the wavelength.
You can use v=R to calculate the frequency, then use c/v to calculate the wavelength.
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Re: Achieve Hw #8
Yes, you can just use the equation as stated in the last response, however, in this variant of the equation make sure that the n1 is the final energy level (n=1) and the n2 is the initial energy level (n=6). In another variation of the equation, where R is negative, n1 is the initial and n2 is the final. So just be courteous of which variable corresponds to what, instead of just plug and chug.
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Re: Achieve Hw #8
Hey! just use the equation frequency = R((1/nfinal^2)-(1/ninitial^2)), and remember, frequency is speed of light/wavelength!
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Re: Achieve Hw #8
You can solve this problem by first using the Rydberg equation: frequency = ((1/(n initial)^2) - (1/(n final)^2)) to calculate the frequency of the emitted wave.
Then you can convert this value to wavelength by using the speed of light equation: c = frequency x wavelength.
Then you can convert this value to wavelength by using the speed of light equation: c = frequency x wavelength.
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Re: Achieve Hw #8
Hello!! As for question #8 on the Achieve, since it is asking you for the wavelength, you must use Rydberg's equation and then you would use the frequency to find the wavelength. As for Rydberg's equation that is on the Constants and Equations Sheet, you would always plug in the number that is larger into n2 because when you square a number in the denominator, you obtain a smaller number. Therefore, you would plug in 1 for n1 and 6 for n2. There after, plug in the frequency found into c = wavelength * frequency. Hope this helps!
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Re: Achieve Hw #8
Make sure to convert the wavelength to nanometers! Achieve sometimes wants the answer in Angstroms or meters or nanometers and it can be easy to forget what exactly the question was asking for.
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Re: Achieve Hw #8
You would use the equation v=R((1/(n1)^2)/(1/(n2)^2)). Make sure n1 is the lower energy level and n2 is the larger energy level. Once you get that number you can divide it by the speed of light to get the wavelength in meters. At that point you can convert to nm by dividing by 10^9. Hope this helps!
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Re: Achieve Hw #8
Hello, to solve this problem you would first need to use the Rydberg equation, R=(1/nfinal^2 - 1/ ninitial^2). Once you get your frequency, to find the wavelength you would use the formula: c= frequency x wavelength. Remember to convert your wavelength to nm by dividing your answer by 10^-9. I hope this is helpful!
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Re: Achieve Hw #8
You can start by using the equation v=R((1/(n1)^2)/(1/(n2)^2)). Where n1 corresponds to the lower energy level, and n2 corresponds to the higher energy level. R = 3.29x10^15! Remember that this equation gives you a frequency!
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Re: Achieve Hw #8
To solve this equation, you'd use the rydberg equation (which also uses the rydberg constant) and plug the n values into the equation.
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Re: Achieve Hw #8
hi! for #8, i used
1/lambda = (1.0974 x 10^7 m^-1)(1/n1^2 - 1/n2^2) to find the wavelength in meters, and then I converted it into nanometers. the math takes a bit of time, but if should give you the right answer!
1/lambda = (1.0974 x 10^7 m^-1)(1/n1^2 - 1/n2^2) to find the wavelength in meters, and then I converted it into nanometers. the math takes a bit of time, but if should give you the right answer!
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