Achieve Hw #8


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JasmineReyes-2K
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Achieve Hw #8

Postby JasmineReyes-2K » Fri Oct 22, 2021 11:36 pm

Hi!

I am very confused on how to start question 8 of our homework, can anyone give me any advice?


"Calculate the wavelength, in nanometers, of the spectral line produced when an electron in a hydrogen atom undergoes the transition from the energy level n=6
to the level n=1."

Yuzhe Yuan
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Re: Achieve Hw #8

Postby Yuzhe Yuan » Fri Oct 22, 2021 11:42 pm

Hi,

You can use v=R to calculate the frequency, then use c/v to calculate the wavelength.

Anthony Tam
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Joined: Fri Sep 24, 2021 7:04 am

Re: Achieve Hw #8

Postby Anthony Tam » Sat Oct 23, 2021 6:09 pm

Yes, you can just use the equation as stated in the last response, however, in this variant of the equation make sure that the n1 is the final energy level (n=1) and the n2 is the initial energy level (n=6). In another variation of the equation, where R is negative, n1 is the initial and n2 is the final. So just be courteous of which variable corresponds to what, instead of just plug and chug.

Joseph Lee
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Joined: Fri Sep 24, 2021 6:35 am

Re: Achieve Hw #8

Postby Joseph Lee » Sat Oct 23, 2021 6:25 pm

Hey! just use the equation frequency = R((1/nfinal^2)-(1/ninitial^2)), and remember, frequency is speed of light/wavelength!

michaelcrisera
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Re: Achieve Hw #8

Postby michaelcrisera » Sat Oct 23, 2021 7:14 pm

You can solve this problem by first using the Rydberg equation: frequency = ((1/(n initial)^2) - (1/(n final)^2)) to calculate the frequency of the emitted wave.
Then you can convert this value to wavelength by using the speed of light equation: c = frequency x wavelength.

Jayden Tan 2L
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Joined: Fri Sep 24, 2021 7:32 am

Re: Achieve Hw #8

Postby Jayden Tan 2L » Sat Oct 23, 2021 8:15 pm

Hello!! As for question #8 on the Achieve, since it is asking you for the wavelength, you must use Rydberg's equation and then you would use the frequency to find the wavelength. As for Rydberg's equation that is on the Constants and Equations Sheet, you would always plug in the number that is larger into n2 because when you square a number in the denominator, you obtain a smaller number. Therefore, you would plug in 1 for n1 and 6 for n2. There after, plug in the frequency found into c = wavelength * frequency. Hope this helps!

Emily Chen 1G
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Re: Achieve Hw #8

Postby Emily Chen 1G » Sat Oct 23, 2021 8:23 pm

Make sure to convert the wavelength to nanometers! Achieve sometimes wants the answer in Angstroms or meters or nanometers and it can be easy to forget what exactly the question was asking for.

Clarence Clavite 2K
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Re: Achieve Hw #8

Postby Clarence Clavite 2K » Sat Oct 23, 2021 9:03 pm

You would use the equation v=R((1/(n1)^2)/(1/(n2)^2)). Make sure n1 is the lower energy level and n2 is the larger energy level. Once you get that number you can divide it by the speed of light to get the wavelength in meters. At that point you can convert to nm by dividing by 10^9. Hope this helps!

Isabella Perez Dis3L
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Joined: Fri Sep 24, 2021 6:38 am

Re: Achieve Hw #8

Postby Isabella Perez Dis3L » Sat Oct 23, 2021 10:58 pm

Hello, to solve this problem you would first need to use the Rydberg equation, R=(1/nfinal^2 - 1/ ninitial^2). Once you get your frequency, to find the wavelength you would use the formula: c= frequency x wavelength. Remember to convert your wavelength to nm by dividing your answer by 10^-9. I hope this is helpful!

Macy_Anderson_2F
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Joined: Fri Sep 24, 2021 5:02 am

Re: Achieve Hw #8

Postby Macy_Anderson_2F » Sat Oct 23, 2021 11:24 pm

You can start by using the equation v=R((1/(n1)^2)/(1/(n2)^2)). Where n1 corresponds to the lower energy level, and n2 corresponds to the higher energy level. R = 3.29x10^15! Remember that this equation gives you a frequency!

August Blum Dis 3D
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Joined: Fri Sep 24, 2021 5:30 am

Re: Achieve Hw #8

Postby August Blum Dis 3D » Sun Oct 24, 2021 1:53 pm

To solve this equation, you'd use the rydberg equation (which also uses the rydberg constant) and plug the n values into the equation.

Teresa Dinh 3L
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Joined: Fri Sep 24, 2021 6:55 am

Re: Achieve Hw #8

Postby Teresa Dinh 3L » Sun Oct 24, 2021 3:20 pm

Hi,

To solve this, use the Rydberg's equation!

Abby 2B
Posts: 100
Joined: Fri Sep 24, 2021 7:17 am

Re: Achieve Hw #8

Postby Abby 2B » Sun Oct 24, 2021 9:22 pm

hi! for #8, i used
1/lambda = (1.0974 x 10^7 m^-1)(1/n1^2 - 1/n2^2) to find the wavelength in meters, and then I converted it into nanometers. the math takes a bit of time, but if should give you the right answer!


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