Problem 14.21c

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Daniel_Sands3L
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Problem 14.21c

Postby Daniel_Sands3L » Tue Feb 02, 2016 11:52 pm

In problem 14.21c, the problem provides the following cell diagram for us to find the cell potential: .

How would you perform the oxidation at the anode provided that is oxidized to ? I'm a bit stuck here.

Chem_Mod
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Re: Problem 14.21c

Postby Chem_Mod » Wed Feb 03, 2016 11:15 am

Cl isn't the ion undergoing redox in this diagram. On the left, you have Hg-> Hg+ and on the right, you have Hg-> Hg 2+. In this case, Hg is being both oxidized and reduced.

Daniel_Sands3L
Posts: 13
Joined: Fri Sep 25, 2015 3:00 am

Re: Problem 14.21c

Postby Daniel_Sands3L » Wed Feb 03, 2016 1:01 pm

Is the Cl- ion in the cell diagram shown as the product of the oxidation half reaction then? Why is it included?

Ronald Yang 2F
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Re: Problem 14.21c

Postby Ronald Yang 2F » Thu Feb 04, 2016 10:27 pm

Because the Cl- is necessary for the oxidation half-reaction to occur. You also include species that is needed in the half-reaction. Also, on the right side resembling the cathode, isn't it Hg22+ -> Hg?


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