Need help on galvanic cells

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KaylaH
Posts: 26
Joined: Fri Sep 25, 2015 3:00 am

Need help on galvanic cells

Postby KaylaH » Sat Feb 06, 2016 4:06 pm

How do you tell how which substances are the products and the reactants for galvanic cells?
For example, in question 14.9 (b) they give you C(gr)|H2(g)|H+(aq)||Cl-(aq)|Cl2(g)|Pt(s)...and for the anode reaction it is 2H+(aq) +2e---->H2(g) but for the cathode it is Cl2(g)+2e---->2Cl-
How do you know to put Cl2 (g) as a product?
Is it because it is being reduced?

hannaluong4E
Posts: 22
Joined: Fri Sep 25, 2015 3:00 am

Re: Need help on galvanic cells

Postby hannaluong4E » Sat Feb 06, 2016 4:17 pm

Yes! The left side of the cell diagram represents the anode (oxidation reaction) and the right side represents the cathode (reduction reaction). So oxidation H2 --> 2H+ + 2e- and reduction Cl2 + 2e- --> 2Cl-

The C(gr) and Pt(s) are not part of either half reactions because they are the inert electrodes used to conduct the e-.


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