14.9

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Yunna Gu
Posts: 26
Joined: Fri Sep 25, 2015 3:00 am

14.9

Postby Yunna Gu » Sun Feb 07, 2016 9:34 pm

How do you know the moles of electron for part a is 2, and the moles of electron for part b is 6?

Kaitlin Ross 3E
Posts: 25
Joined: Fri Sep 25, 2015 3:00 am

Re: 14.9

Postby Kaitlin Ross 3E » Sun Feb 07, 2016 9:52 pm

The number of moles in the equation to calculate Gibbs free energy are the number of moles of electrons transferred, so when you write out the half reactions for the redox in reaction you will be able to see that in part a there were 2 moles of electrons transferred and in part b there were 6 moles.
a) 2e- + 2Ce^4+ ---> 2Ce^3+
3I- ---> I3^- + 2e-

b) 6Fe^3+ + 6e- ---> 6Fe^2+
2Cr^3+ + 7H2O ---> Cr2O7^2- + 14H+ + 6e-


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