### Midterm 2013 #7

Posted:

**Tue Feb 09, 2016 5:26 pm**The first part of this question that requires you to calculate the cell potential does not make sense to me. The cell potential of the cathode (the half equation involving Br2) is positive, which makes sense, however the cell potential for the anode (Mn2+ equation) should have the sign of its given cell potential reversed (from +1.49V to -1.49V) since the equation is reversed. However, when the final cell potential is calculated, the equation is not E = (+1.07V) - (-1.49V) = +2.56V. Is the solution incorrect or have I misunderstood how to solve for E?