## Vivek Week 8 wksht #4 [ENDORSED]

hayley prinstein 2I
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### Vivek Week 8 wksht #4

I was wondering if anyone could explain why you dont flip the Ecell of the anode in question 4, since it is given in reduction form? I thought since it is the anode and its being oxidized we had to flip the sign. Thanks!

HaoYun_Liew_1I
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### Re: Vivek Week 8 wksht #4  [ENDORSED]

You can, but its just a difference in how the formula is understood.

If you do the flip, -1.68, becomes 1.68, and then you do Ecathode + Eanode = -1.18 + (1.68) = 0.5

You could also just not do the flip, only the difference is the formula would be Ecathode - Eanode = -1.18 -(-1.68) = 0.5; which is that is shown in the problem

In both cases, the Ecell is still 0.5, just depends on which formula u use.

The flip is if you simply just want to simplify and add two values, instead of doing the part where you subtract a negative number (which is addition, since -*- = +)

Chem_Mod
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### Re: Vivek Week 8 wksht #4

HaoYun_Liew_1I wrote:You can, but its just a difference in how the formula is understood.

If you do the flip, -1.68, becomes 1.68, and then you do Ecathode + Eanode = -1.18 + (1.68) = 0.5

You could also just not do the flip, only the difference is the formula would be Ecathode - Eanode = -1.18 -(-1.68) = 0.5; which is that is shown in the problem

In both cases, the Ecell is still 0.5, just depends on which formula u use.

The flip is if you simply just want to simplify and add two values, instead of doing the part where you subtract a negative number (which is addition, since -*- = +)

Exactly, it just depends on what formula you want to use. Either will work--just stick to one so you get a routine down for the test.
-Vivek