6M.11
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Re: 6M.11
To solve for thsi you need to do the following steps according to my understanding:
Identify Oxidation and Reduction Half-Reactions
Compare Standard Reduction Potentials
Identify Reducing and Oxidizing Agents
By doing those three steps you should be able to generate an accurate answer. I hope that helps!!
Identify Oxidation and Reduction Half-Reactions
Compare Standard Reduction Potentials
Identify Reducing and Oxidizing Agents
By doing those three steps you should be able to generate an accurate answer. I hope that helps!!
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- Posts: 82
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Re: 6M.11
Hi, first you have to look for the standard reduction potential in the appendix that involves Co2+/Co and Ti3+/Ti2+. the standard reduction potential for Co2+/Co is -0.28V, and for Ti3+/Ti2+, it's -0.37. It would be more favorable for the overall E to be positive (spontaneous), so making Ti3+/Ti2+ the anode and Co2+/Co the cathode would yield an overall positive value. Eknot= cathode-anode= -0.28-(-0.37)=0.09V.
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- Posts: 37
- Joined: Wed Feb 15, 2023 8:20 am
Re: 6M.11
So the anode is the one getting oxidized so it is a reducing agent and the cathode is getting reduced so it is an oxidizing agent. I believe in cases where it could be either way you look at the most electrons passed so in this case the CO2+ to CO is the cathode which is an oxidizing agent being reduced.
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