Homework 14.37

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Taravat_Lakzian_1C
Posts: 18
Joined: Wed Sep 21, 2016 2:56 pm

Homework 14.37

Postby Taravat_Lakzian_1C » Sun Feb 05, 2017 10:56 pm

In #37, it asks to determine the potential of each of the following cells. How would you determine the potential of the cell when for example you are given:
Pt(s)|H2(g, 1.0 bar)|HCl(aq, 0.075 M)||HCl (aq, 1.0 mol/L)|H2(g, 1.0 bar)|Pt(s)
Any help would be appreciated!

Aileen Nguyen 3N
Posts: 26
Joined: Wed Sep 21, 2016 2:56 pm
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Re: Homework 14.37

Postby Aileen Nguyen 3N » Mon Feb 06, 2017 5:08 pm

You would use E˚cell = E˚cathode - E˚anode with E˚ at the electrodes being the the electron potential for the half reaction.

2H+ (aq, 1.0 M) +2e- ----> H2 (g, 1 atm) E˚cathode = 0 V
H2 (g, 1 atm) ----> 2H+ (aq, .075 M) +2e- E˚anode = 0 V
2H+ (aq, 1.0 M) +2e- + H2 (g, 1 atm) ----> 2H+ (aq, .075 M) +2e- + H2 (g, 1 atm)
E˚cell=0.0 V
E= E˚- (.025693 /n) ln(([H+, .075M]^2 * Subscript[P, H2])/([H+, .075M]^2 * Subscript[P, H2]))
E= 0.0V-( 0.025693V/2) ln(([.075M]^2 x 1 atm)/( [1.0M]^2 x 1 atm))
E= .0129 V LN (0.075)^2= +0.067 V


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