Homework 14.11

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Kelsey Jug 1J
Posts: 38
Joined: Wed Sep 21, 2016 2:59 pm

Homework 14.11

Postby Kelsey Jug 1J » Wed Feb 08, 2017 11:52 pm

The solution states that Ni^2+ (aq) + 2e ---> Ni (s) has E(anode) = -0.23 V. The solution proceeds to flip the reaction so that the reaction is Ni (s) ----> Ni^2+ (aq) + 2e but does not switch the sign of the E(anode) to +0.23V. Aren't we always suppose to change the sign of the voltage when we reverse the reaction?

Bola_G_3H
Posts: 12
Joined: Wed Sep 21, 2016 2:56 pm

Re: Homework 14.11

Postby Bola_G_3H » Thu Feb 09, 2017 2:32 pm

The solution Manual used the formula Ecell = Cathode - anode. However, if you switched the sign for the anode and then added it to the cathode value then you would still get the same answer.


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