## Homework help 14.11 [ENDORSED]

tobeylee_1C
Posts: 10
Joined: Sat Jul 23, 2016 3:00 am

### Homework help 14.11

I was doing part all the parts of the question when reversing the reduction reactions of the anode to make it the oxidation part of the redox reaction I notice that the solutions manual didn't change the sign of E even though it was reversed. I was wondering if I was doing it wrong or there's an error in the solutions manual.

Maggie Bui 1H
Posts: 35
Joined: Fri Jul 22, 2016 3:00 am
Been upvoted: 1 time

### Re: Homework help 14.11  [ENDORSED]

Though it doesn't explicitly reverse the reduction potential, the solutions manual does essentially the same thing. Instead of reversing the reduction potential and then adding the two half-reaction potentials to get the standard cell potential, it just subtracts the reduction potential of the anode from that of the cathode.

$E^ {0} = E_{cathode} - E_{anode}$

In the equation above, the signs of E don't change, but the reduction potential of the anode is subtracted from that of the cathode.

$-E_{anode}$
$(-E_{anode}) + E_{cathode} = E^{0}$

This equation is a depiction of what we do when we reverse the reduction potential before adding. The two are equivalent.

Ariana Murillo 2O
Posts: 21
Joined: Tue Jul 19, 2016 3:00 am

### Re: Homework help 14.11

For question 11, how did they know to reverse the anode half-reaction?

tobeylee_1C
Posts: 10
Joined: Sat Jul 23, 2016 3:00 am

### Re: Homework help 14.11

Ariana the anode is reversed because it oxidizes and half-reaction given is a reduction form of the anode.

JaeHoCho1B
Posts: 16
Joined: Sat Jul 09, 2016 3:00 am

### Re: Homework help 14.11

When we are solving these questions, will be given the the standard potential on the exam?

Zoe Robertson 2H
Posts: 28
Joined: Fri Jun 17, 2016 11:28 am

### Re: Homework help 14.11

Is the the cathode in this example not given as an oxidation instead of reduction? Don't you read the diagram inside out?