2013 Final Exam practice

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Michael Lonsway 3O
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Joined: Wed Sep 21, 2016 2:57 pm

2013 Final Exam practice

Postby Michael Lonsway 3O » Fri Mar 10, 2017 11:25 pm

For part c of this problem how do we get n=6? I looked at the reaction and it didn't look like there were 6 moles in the system.
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Greta Tobin 2F
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Joined: Wed Sep 21, 2016 2:57 pm

Re: 2013 Final Exam practice

Postby Greta Tobin 2F » Sat Mar 11, 2017 11:39 am

For the 2013 final question number 1B, How do we know to use Cv=3/2(R)?
Because the formula just says deltaS=nCln(T2/T1) and doesn't specify what kind of C to use?

Henry_Shin_3B
Posts: 14
Joined: Wed Sep 21, 2016 2:55 pm

Re: 2013 Final Exam practice

Postby Henry_Shin_3B » Sun Mar 12, 2017 10:18 pm

the "n" in the Nernst equation actually doesn't really have anything to do with how many moles of atoms there are in the equation, it instead refers to how many electrons were involved. If you see the original two half reactions, you'll see that the oxidation reaction lost 6 electrons and that the reduction reaction gained 6 electrons.

So n=6.


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