14.13 (b)

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Hannah Guo 3D
Posts: 56
Joined: Fri Sep 29, 2017 7:06 am

14.13 (b)

Postby Hannah Guo 3D » Sun Feb 18, 2018 5:45 pm

Can someone explain why we still need Pt(s) on the left side of the salt bridge even if there is I2(s)? Doesn't I2(s) already act as a conductor?
Thank you!

Nishma Chakraborty 1J
Posts: 51
Joined: Fri Sep 29, 2017 7:04 am

Re: 14.13 (b)

Postby Nishma Chakraborty 1J » Sun Feb 18, 2018 6:02 pm

I think it's because I2, even though it's in its solid state, is a nonmetal. A metal is needed to transfer electrons from the anode to cathode, so Pt(s) has to be used. Hope this helps!

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