14.15A

[Dylan Mai 1D]

How do you know that the Anode reaction is AgBr + e- to Ag (s) + Br - and not Br2 + 2e- to 2Br-?

[sahajgill]

There is no 2Br in the equation

[Swetha Sundaram 1E]

For this question, I was confused in how oxidation numbers were distributed in the original question because I thought Ag was +1 and Br was -1 and they stayed the same throughout because the ions split but this does not make sense in regards to reduction/oxidation half-reactions.

[Christy Lee 2H]

For this problem the cell diagram in the solutions manual divides Ag(s) and AgBr(s) on the anode side with a vertical line. Can someone explain why they aren't separated by a comma even though they're the same phase?

[Jana Sun 1I]

For this problem the cell diagram in the solutions manual divides Ag(s) and AgBr(s) on the anode side with a vertical line. Can someone explain why they aren't separated by a comma even though they're the same phase?

This is addressed in this thread: viewtopic.php?f=140&t=28121. I also think it might be because Ag(s) and AgBr(s) aren't ions. On page 574 of the book, it says that ions are only separated by a comma in the same state.