14.13 part D

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Emily Mei 1B
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Joined: Fri Sep 29, 2017 7:04 am

14.13 part D

Postby Emily Mei 1B » Mon Feb 19, 2018 3:04 pm

The skeleton equation was Au+(aq) + --> Au(s) + Au3+(aq). Can someone explain why the the anode half reaction is Au3+(aq) + 3e- -> Au(s)?

Gianna Apoderado 1B
Posts: 57
Joined: Fri Sep 29, 2017 7:04 am

Re: 14.13 part D

Postby Gianna Apoderado 1B » Mon Feb 19, 2018 5:17 pm

I was wondering this as well, since Au3+ is supposed to be on the products side. It may have been a solution manual error.

Clarisse Wikstrom 1H
Posts: 63
Joined: Fri Sep 29, 2017 7:05 am

Re: 14.13 part D

Postby Clarisse Wikstrom 1H » Mon Feb 19, 2018 5:20 pm

Same, I thought it would have been Au+(aq) --> Au3+(aq) + 2e- , with Pt(s) as the conducting solid....


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