14.19

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Gianna Apoderado 1B
Posts: 57
Joined: Fri Sep 29, 2017 7:04 am

14.19

Postby Gianna Apoderado 1B » Mon Feb 19, 2018 5:08 pm

In the calculation of the standard potential for the left (Metal) reduction, how come the sign of the Cu oxidation potential doesn't become negative?

Initially, I had:
Eo(left) = Eo(right) - Eo(cell) = -0.34 - 0.689 = -1.029

But when I checked the answer, it was -0.349, meaning the potential of the Cu oxidation was left positive.

Matthew Lin 2C
Posts: 30
Joined: Fri Sep 29, 2017 7:06 am

Re: 14.19

Postby Matthew Lin 2C » Mon Feb 19, 2018 8:47 pm

Because the equation is actually E(cell)= E(cathode) - E(anode)
Thus, E(cathode)= E(cell) + E(anode) = -0.689+0.34 = -0.349 V

Hope this helps!


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