4.13 part b

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4.13 part b

Postby mayasinha1B » Mon Feb 19, 2018 8:28 pm

Why is the Pt necessary on the left side. I thought it was only necessary when there is no solid metal present, but there is I2 solid present. The solutions manual explained that it is because both oxidized and reduced species are in the same solution, but how do we know that it wasn't given to us. How is this any different from any of the other half reactions where only one half of the reaction need Pt(s). Please help

Aditya Pimplaskar 1J
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Re: 4.13 part b

Postby Aditya Pimplaskar 1J » Tue Feb 20, 2018 9:32 pm

Though I2 is given as a solid in the reaction, it isn't used as the electrode as it is limited in its ability to conduct electron flow. We use platinum, which is more conductive, for our electrodes in this case.

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