HW 14.9

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Peter Dis1G
Posts: 97
Joined: Fri Sep 29, 2017 7:04 am

HW 14.9

Postby Peter Dis1G » Tue Feb 20, 2018 6:31 pm

I fail to understand the number of mols. How to figure that out from the equation? Thanks.

Lisa Tang 1C
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Joined: Fri Sep 29, 2017 7:05 am
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Re: HW 14.9

Postby Lisa Tang 1C » Tue Feb 20, 2018 6:44 pm

To get the number of mols of electrons, you write a half reaction for both the oxidation and reduction. In 14.9a, for example, 2Ce4+(aq) is reduced while 3I-(aq) is oxidized. The two half reactions:
2Ce4+(aq) + 2e- --> 2Ce3+(aq)
3I-(aq) --> I3-(aq) + 2e-
From this, you can see that 2 electrons were transferred. Hope this helps.

Peter Dis1G
Posts: 97
Joined: Fri Sep 29, 2017 7:04 am

Re: HW 14.9

Postby Peter Dis1G » Tue Feb 20, 2018 6:57 pm

That helps alot!


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