14.23a

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Karen Ung 2H
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Joined: Fri Sep 29, 2017 7:04 am
Been upvoted: 1 time

14.23a

Postby Karen Ung 2H » Tue Feb 20, 2018 11:16 pm

Why does the left side of the cell diagram not have a Pt(s), and the right side does?

This is the reaction: 2(NO3)-(aq) + 8H+(aq) + 6Hg(l) -> 3(Hg2)2+(aq) + 2NO(g) + 4H2O(l)

Eli Aminpour 2K
Posts: 50
Joined: Fri Sep 29, 2017 7:04 am

Re: 14.23a

Postby Eli Aminpour 2K » Tue Feb 20, 2018 11:32 pm

First, the inert electrode has to be placed in the cell diagram because the electrodes are made of aqueous solutions (meaning there are no conducting solids). The platinum tends to go on the right side of the cell diagram (cathode-reduction) because it only transfers electrons. It does not exchange ions. this website helps
chem.libretexts.org/Core/Analytical_Chemistry/Electrochemistry/Voltaic_Cells/Electrochemical_Cell_Conventions

Rakhi Ratanjee 1D
Posts: 59
Joined: Fri Sep 29, 2017 7:04 am

Re: 14.23a

Postby Rakhi Ratanjee 1D » Wed Feb 21, 2018 12:47 am

Why are there two ions on the right side: NO3- and H+ ?


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