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Why is the 2H+ + 2e- => H2 the reduction reaction? The standard reduction potential for that reaction is 0, whereas the the standard reduction potential for the other reaction 2Cl- => Cl2 + 2e- is +1.36, which is greater and therefore has stronger oxidizing power and should be the reduction reaction?
Because anode is always written on the left side of the cell diagram, you still have to calculate the Ecell = Ecathode - Eanode, which does give you a negative voltage. This tells you that the reaction is not spontaneous, and that the electrons would flow in the opposite direction.
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