14.107 Determining K

[Jessica Yang 1J]

Hi I am confused with how we are supposed to calculate K at pH= 1 and pH= 14. In the solutions manual, it states that the K at pH=14 is (1.0 x 10^-14) / (1.0). Where did we get the 1.0 M from? Also for the pH=1 the K is (0.1/ 1.0 x 10^-14). Where did the 1.0 x 10^-14 come from?

[Clarisse Wikstrom 1H]

K= [H+]/[OH-]

@pH 1: 1=-log[H+] --> [H+] = 1x10^-1 M
therefore, pOH 13: [OH-]= 1x10^-13 M

@pH 14: [H+]= 1x10^-14 M
therefore, pOH 0: [OH-]= 1x10^0= 1.0 M

There is an error in the solution manual for this problem, so I'd check on Lavelle's website.