### 14.19

Posted:

**Wed Feb 21, 2018 10:58 pm**A student was given a standard Cu(s) 0 Cu (aq) half-cell and another half-cell containing an unknown metal M immersed in 1.00 m M(NO3)2(aq). When the copper was connected as the anode at 25 C, the cell potential was found to be -0.689 V. What is the reduction potential for the unknown M2 /M couple?

Since copper is the anode, then Cu(s) --> Cu2+(aq) + 2e-

And the reduction potential is .34

So shouldn't the cell potential be -.689(cathode) - .34 (anode) = -1.029?

The answer is -.698+ .34 = -.349

why is this?

Since copper is the anode, then Cu(s) --> Cu2+(aq) + 2e-

And the reduction potential is .34

So shouldn't the cell potential be -.689(cathode) - .34 (anode) = -1.029?

The answer is -.698+ .34 = -.349

why is this?