14.13 c
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Ashley Davis 1I
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14.13 c
Could someone explain why for 14.13 part c  \rightarrow Au(s) + Au^{3+}(aq))
that one of the half-reactions has Au3+ as a reactant and Au(s) as a product when they are both on the same side in the original equation given? I thought the two half reactions would be Au+(aq) + 1e- → Au(s) as the reduction half and Au+(aq) → Au3+(aq) + 2e- as the oxidation half.
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Alyssa Parry Disc 1H
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