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I had the same question because gold solid is not a reactant in the overall reaction. However, when you balance the half reactions (with gold solid being the reactant of the second half reaction) and sum them, the overall reaction matches the reaction stated in the problem.
After multiplying the first reaction by 3 the Au on the left side of half reaction 2 will cancel out one of these on half reaction 1. If you are wondering why the electrons are on different sides for the reactions this is simply because Au is losing and gaining electrons. These are unique reactions where a substance is being oxidized and reduced at the same time.
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