14.23 part a

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Emilie Hoffman 1E
Posts: 55
Joined: Fri Sep 29, 2017 7:04 am

14.23 part a

Postby Emilie Hoffman 1E » Fri Feb 23, 2018 12:12 am

In the solutions manual, there is no listed electrode for the oxidation part of this reaction, while platinum on serves as such on the cathode side. Furthermore, none of the oxidation reactants or products are solids. Can someone clear up what is happening here?

Here is the original problem:
For each reaction that is spontaneous under standard conditions, write a cell diagram, determine the standard cell potential, and calculate deltaG for the reaction:
(a) 2 NO3(aq) + 8 H+(aq) + 6 Hg(l) --> 3 Hg2(2+)(aq) + 2 NO(g) + 4 H2O(l)

Hannah Krusenoski 2L
Posts: 31
Joined: Fri Sep 29, 2017 7:06 am

Re: 14.23 part a

Postby Hannah Krusenoski 2L » Fri Feb 23, 2018 1:30 am

Liquid Hg can also act as an electrode when it is in the equation.


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