Reaction Favoring Products

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Sarah Sharma 2J
Posts: 33
Joined: Fri Sep 29, 2017 7:05 am

Reaction Favoring Products

Postby Sarah Sharma 2J » Fri Feb 23, 2018 11:25 am

Can someone please explain to me why when the cathode has a higher E value than the anode, the reaction favors the products?

Wenting Hu 2H
Posts: 33
Joined: Fri Sep 29, 2017 7:06 am

Re: Reaction Favoring Products

Postby Wenting Hu 2H » Fri Feb 23, 2018 12:08 pm

When cathode has a higher value than anode, it makes the E positive since E=Ecathode=Eanode. We now know that the reaction favors the products because G=-nFE. If E is positive, G is negative and therefore, the reaction will spontaneously form products.

TarynLane2J
Posts: 30
Joined: Sat Jul 22, 2017 3:00 am

Re: Reaction Favoring Products

Postby TarynLane2J » Fri Feb 23, 2018 12:37 pm

Another way you can think of it is that E represents standard Reduction potential, not oxidation potential, so you want E for the cathode to be big (since reduction occurs at the cathode) and E for the anode to be small, preferably negative, (since oxidation occurs at the anode). If this is true then E of the total cell will be positive, and G will be negative, which means it is spontaneous.


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