Calculating n in the Nernst Equation
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Calculating n in the Nernst Equation
I have a question about the variable n in the Nernst Equation. I have read that it correlates to the number of electrons transferred across the reaction. However, how is this calculated when there are 3 electrons added on the reactants side of the equation and two added to the products side? Do you do products minus reactants, or add them together for an overall total, or something else? Someone please explain!
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Re: Calculating n in the Nernst Equation
Hey,
When trying to find n in the nerst equation, and there is an uneven amount of electrons on each side, you usually have to balance out the equations so that the electrons cancel. The final amount of electrons after you balance is what you use for n.
When trying to find n in the nerst equation, and there is an uneven amount of electrons on each side, you usually have to balance out the equations so that the electrons cancel. The final amount of electrons after you balance is what you use for n.
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Re: Calculating n in the Nernst Equation
Since you have different amounts of electrons being transferred, you want to find the least common multiple of those two coefficients. In the case of 3 and 2, the least common multiple is 6. So multiply the reaction with 3 electrons on the reactant side by 2 and multiply the reaction with 2 electrons on the products side by 3 that way there are 6 on each side, which will then cancel out. Since 6 was the least common multiple, it will also be your n value.
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