Test 2 Question 6 Part D

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Gwen Peng 1L
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Joined: Sat Jul 22, 2017 3:01 am

Test 2 Question 6 Part D

Postby Gwen Peng 1L » Mon Mar 05, 2018 11:55 pm

For this question wouldn't you just use the formula: E(cell)=E(cathode)-E(anode), which means it would be +2.07 V- (-1.24 V)= +3.31 V?

Anna Goldberg 2I
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Joined: Fri Sep 29, 2017 7:04 am
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Re: Test 2 Question 6 Part D

Postby Anna Goldberg 2I » Mon Mar 05, 2018 11:59 pm

Yes, that is the formula that you use.
I would have to know the values for E cathode and E anode in order to tell you if your E cell is correct.

Beza Ayalew 1I
Posts: 58
Joined: Fri Sep 29, 2017 7:07 am

Re: Test 2 Question 6 Part D

Postby Beza Ayalew 1I » Tue Mar 06, 2018 12:40 am

if you used the standard potentials from the equations given on the back of test and didn't flip the signs, and didn't confuse the cathode vs the anode, your work is fine so your answer should be right


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