14.13 c

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14.13 c

Postby sofiakavanaugh » Thu Mar 15, 2018 12:19 pm

For this one you had to write the 1/2 rxn, balanced equation, calculate Eo cell and write the cell diagram for the unbalanced rxn: Cl2(g) +H2(g) --> HCl(aq)

For the cell diagram the answer is Pt(s) | H2(g) | H+(aq) || Cl2(g) | Cl-(aq) | Pt (s) , but I got it the other way around. Why is that wrong? Does the anode or cathode come first?


Janine Chan 2K
Posts: 71
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Re: 14.13 c

Postby Janine Chan 2K » Thu Mar 15, 2018 12:38 pm

The anode should be written on the left and the cathode should be on the right. In this reaction, Cl2 is being reduced, so the half reaction with Cl2 and Cl- is on the right.

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