14.13 B

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Jesse_torres2H
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Joined: Thu Jul 27, 2017 3:00 am

14.13 B

Postby Jesse_torres2H » Fri Mar 16, 2018 3:07 pm

This question you are supposed to write the cell diagram for the equation Ce^4+(aq) + I^-(aq)---> I2(s) + Ce^3+(aq) the solutions manual has the cell diagram as Pt(s)|I-(aq)|I(s)||Ce4+(aq),Ce3+(aq)|Pt(s). Why do we need the Pt at the anode I thought solids, in this case I, could be used as electrodes.

Seth_Evasco1L
Posts: 54
Joined: Thu Jul 27, 2017 3:00 am

Re: 14.13 B

Postby Seth_Evasco1L » Fri Mar 16, 2018 3:14 pm

Solids can be used as electrodes but only if they are able to conduct electricity. Iodine (s), being a halogen, is a nonmetal and is therefore unable to conduct electricity. This is why a platinum electrode is utilized at the anode to act as an inert metal that will assist in conducting electricity.

Rachel Wang
Posts: 49
Joined: Fri Sep 29, 2017 7:04 am

Re: 14.13 B

Postby Rachel Wang » Fri Mar 16, 2018 4:53 pm

The electrode is a solid metal that can conduct electricity. I2 is a solid halogen and therefore unable to conduct electricity -> hence the platinum.

Angela 1K
Posts: 80
Joined: Fri Sep 29, 2017 7:05 am

Re: 14.13 B

Postby Angela 1K » Sat Mar 17, 2018 5:18 pm

Do you think on a test, they would expect us to already know that I2 is a halogen and can't conduct electricity, and thus we need Pt(s), or do you think they'd explicitly mention that on a test?


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