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This question you are supposed to write the cell diagram for the equation Ce^4+(aq) + I^-(aq)---> I2(s) + Ce^3+(aq) the solutions manual has the cell diagram as Pt(s)|I-(aq)|I(s)||Ce4+(aq),Ce3+(aq)|Pt(s). Why do we need the Pt at the anode I thought solids, in this case I, could be used as electrodes.
Solids can be used as electrodes but only if they are able to conduct electricity. Iodine (s), being a halogen, is a nonmetal and is therefore unable to conduct electricity. This is why a platinum electrode is utilized at the anode to act as an inert metal that will assist in conducting electricity.
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