14.15 A

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Jesse_torres2H
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Joined: Thu Jul 27, 2017 3:00 am

14.15 A

Postby Jesse_torres2H » Fri Mar 16, 2018 3:19 pm

for part a of the question the equation they give is AgBr(s)---->Ag+(aq) + Br-(aq). It then lists the cathode reaction as Ag+(aq) + e- ---->Ag(s). Why does the AgBr turn into just Ag in this case?

Isabella Sanzi 2E
Posts: 54
Joined: Thu Jul 13, 2017 3:00 am

Re: 14.15 A

Postby Isabella Sanzi 2E » Fri Mar 16, 2018 3:32 pm

Unless I am misinterpreting your question, they gave you the full reaction being AgBr --> Ag+ + Br-, and they ask you to write the half reactions for the cell, meaning that you would have to determine what is being oxidized and what is being reduced so that when the two are combined you get the given reaction. That is why you would come up with an answer that only includes Ag, to account for that half reaction. If you refer to the solution manual, you will find that the second half reaction incorporates the other component involved in this reaction. Hopefully this helps!


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