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Postby RenuChepuru1L » Sat Mar 17, 2018 12:45 am

I don't understand for part c why they didn't flip pb^4/pb^2 to match the given equation they end up using a positive 1.67, why?

Liz White 1K
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Re: 14.31

Postby Liz White 1K » Sat Mar 17, 2018 12:56 am

As you can see in the solutions manual for part b), you are supposed to put the oxidated ion over the oxidating ion when it comes to writing out the half reaction for the anode. Since Pb4+ is the result of Pb2+ losing electrons (oxidation is loss), Pb4+ is oxidated, so you divide Pb4+ / Pb2+.

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