Moderators: Chem_Mod, Chem_Admin

Posts: 29
Joined: Fri Sep 29, 2017 7:07 am


Postby Connie2I » Sat Mar 17, 2018 6:22 pm

For 14.15a, when writing a cell diagram for AgBr (s) <-> Ag+(aq) + Br-(aq), is the anode/cathode just assumed to be Ag(s)? And why?

Posts: 63
Joined: Sat Jul 22, 2017 3:01 am
Been upvoted: 1 time

Re: 14.15

Postby ZoeHahn1J » Sat Mar 17, 2018 9:26 pm

Ag is oxidized in the reaction (anode) and Br is reduced (cathode). We can tell which one is oxidized or reduced by how favorable it would be for each atom to either gain or lose an electron; since Br is very electronegative, we can assume that it would take an electron, and that therefore, Ag would lose an electron and be oxidized.

Return to “Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams”

Who is online

Users browsing this forum: No registered users and 2 guests